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  • Provide Solution for RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Fill in the blanks Question 19

Provide Solution for RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Fill in the blanks Question 19

Answers (1)

Answer :   (5 \hat{\imath}-4 \hat{\jmath}+6 \hat{k})+\lambda(3 \hat{\imath}+7 \hat{\jmath}+2 \hat{k})

Hint : Compare the equation with the formula

Given :    \frac{x-5}{3}=\frac{y+4}{7}=\frac{z-6}{2}  

Solution :    We have given line as

                   \frac{x-5}{3}=\frac{y+4}{7}=\frac{z-6}{2}

                     By comparing with equation

                    \frac{x-x 1}{a}=\frac{y-y 1}{b}=\frac{z-z 1}{c}

                    We get given line passes through the point (x1 , x2, x3)

                    i.e. (5 , -4 , 6) and direction ratios are (a ,b ,c) i.e. ( 3 , 7 , 2)

                    Now , we can write vector equation of the line as

                 \vec{A}=(5 \hat{\imath}-4 \hat{\jmath}+6 \hat{k})+\lambda(3 \hat{\imath}+7 \hat{\jmath}+2 \hat{k})

 

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