Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths class 12 chapter 27 Straight Line in Space exercise 27.1 question 8 maths textbook solution

Provide solution for RD Sharma maths class 12 chapter 27 Straight Line in Space exercise 27.1 question 8 maths textbook solution

Answers (1)

Answer :-

(2 \hat{\imath}-\hat{\jmath}+\hat{k})+\lambda(2 \hat{\imath}+7 \hat{\jmath}-3 \hat{k})

Hint :-

\overrightarrow{a}+\lambda \overrightarrow{b}

Given :-

The line passes through (2 , -1 , 1) and parallel to equation  \frac{x-3}{2}=\frac{y+1}{7}=\frac{z-2}{-3}

Solution :-

P.V of (2 , -1 , 1) \Rightarrow \overrightarrow{a}=2 \hat{\imath}-\hat{\jmath}+\hat{k} 

D.R of \frac{x-3}{2}=\frac{y+1}{7}=\frac{z-2}{-3}   is (2 , 7 , -3)

\therefore \overrightarrow{b}=2\hat{i}+7\hat{j}-3\hat{k}

Vector Equation

\overrightarrow{r}=\overrightarrow{a}+\lambda \overrightarrow{b} , where ? is parameter

      = (2 \hat{\imath}-\hat{\jmath}+\hat{k})+\lambda(2 \hat{\imath}+7 \hat{\jmath}-3 \hat{k})

 

Posted by

Infoexpert

View full answer

Similar Questions

Latest Question