Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A ball of mass is dropped from the height of <img alt="10 \mathrm{~m}" src="https://en

A ball of mass0.5 \mathrm{~kg} is dropped from the height of 10 \mathrm{~m}. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is___________ \mathrm{m}. [Use g=10 \mathrm{~m} / \mathrm{s}^{2} ]

Option: 1

5


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{m= 0.5\, kg}
\mathrm{h= 10\, m}
\mathrm{v= 10\left ( \frac{m}{s} \right )}


\mathrm{ \sqrt{2gy}= 10}
\mathrm{ 2\times 10\times y= 100}
\mathrm{ y= 5\, m}

At heights 5 m from the surface or from the top the velocity becomes equal to the magnitude of acceleration due to gravity

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question