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  • A body is released from a height equal to the radius (r) of the earth. The velocity of the body when it strikes the surface of the earth will be : (Given g = acceleration due to gravity on t

A body is released from a height equal to the radius (r) of the earth. The velocity of the body when it strikes the surface of the earth will be :
(Given g = acceleration due to gravity on the earth.)

Option: 1

\sqrt gR


Option: 2

\sqrt\frac{gR}{2}


Option: 3

\sqrt{4 \mathrm{gR}}


Option: 4

\sqrt{2 \mathrm{gR}}


Answers (1)

best_answer

By energy conservation,

K_1+U_1=K_2+U_2

\begin{aligned} & \mathrm{O}-\frac{\mathrm{GMm}}{2 \mathrm{R}}=\frac{1}{2} \mathrm{mv}^2-\frac{\mathrm{GMm}}{\mathrm{R}} \\ & \mathrm{V}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}} \times \frac{\mathrm{R}}{\mathrm{R}}} \\ & \mathrm{V}=\sqrt{\mathrm{gR}} \end{aligned}              

Posted by

Anam Khan

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