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A boy of mass 10 \mathrm{~kg} is attached to a wire of length 0.3 \mathrm{~m}. Its breaking stress is 4.8 \times 10^7 \mathrm{~N} / \mathrm{m}^2. The area of cross-section of wire is 10^{-6} \mathrm{~m}^2. The maximum angular Velocity with which it can be rotated in a horizontal circle without breaking -

Option: 1

2\mathrm{~rad} / \mathrm{s}


Option: 2

3\mathrm{~rad} / \mathrm{s}


Option: 3

4\mathrm{~rad} / \mathrm{s}


Option: 4

5\mathrm{~rad} / \mathrm{s}


Answers (1)

best_answer

The tension in the wire at the axes of rotation -
\begin{aligned} T&=m \omega^2 l \\ f_A&=m \omega^2 l \\ 4.8 \times 10^7 \times 10^{-6}&=10 \times \omega^2 \times 0.3 \\ 4.8 \times 10&=3 \omega^2 \\ \omega^2&=16 \\ \omega&=4 \mathrm{rad} / \mathrm{s} \text { on } \end{aligned}

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rishi.raj

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