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A car travelling at a speed of 60 km/hr can break and stop within a distance of 20 metres . If the car is travelling at twice the speed, i.e.,120 km/hr the stopping distance will be:
 

Option: 1

20 m


Option: 2

40 m


Option: 3

60 m

 


Option: 4

80 m


Answers (1)

best_answer

Let a be the acceleration for both cases.

For automobile, v^2=u^2-2as

Or, {u_1}^2=2as_1

Similarly   {u_2}^2=2as_2

Now, 

\\\(\frac{u_2}{u_1})^2=\frac{s_2}{s_1}\\ \\Or, \left(\frac{120}{60}\right)^2=\frac{s_2}{20} \\ \\Or, s_2=80\ m

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Gunjita

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