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  • A hiker stands on the edge of a cliff 490 above the ground and throws a stone horizontally with an initial speed of 15 m/s. Neglecting air resistance, find the time taken by the stone to

A hiker stands on the edge of a cliff 490 above the ground and throws a stone horizontally with an initial speed of 15 m/s. Neglecting air resistance, find the time taken by the stone to reach the ground. \left(g=9.8 \mathrm{~ms}^{-2}\right)

Option: 1

5s


Option: 2

10s


Option: 3

12s


Option: 4

15s


Answers (1)

best_answer

Since the stone is thrown horizontally, the vertical component of velocity \mathrm{u}_{\mathrm{y}}=0
\begin{aligned} & \therefore \mathrm{h}=0+\frac{1}{2} \mathrm{gt}^2 \\ & \mathrm{~h}=\frac{1}{2} \mathrm{gt}^2 \end{aligned}
This gives the time  t for the stone to reach the ground,
\begin{aligned} & t=\sqrt{\frac{2 h}{g}} \\ & t=\sqrt{\frac{2 \times 490 \mathrm{~m}}{9.8 \mathrm{~ms}^{-2}}}=\sqrt{\frac{980 \mathrm{~m}}{9.8 \mathrm{~ms}^{-2}}} \\ & =\sqrt{100 \mathrm{~s}^2}=10 \mathrm{~s} \end{aligned}

Posted by

Suraj Bhandari

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