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A mass of $50 \mathrm{~kg}$ is placed at the centre of a uniform spherical shell of mass $100 \mathrm{~kg}$ ad radius $50 \mathrm{~m}$ . If the gravitational potential at a point, $25 \mathrm{~m}$ from the centre is $\mathrm{V} \mathrm{kg} / \mathrm{m}$ . The value of $V$ is :

Option: 1 $+2G$
Option: 2 $-60 G$
Option: 3 $-4 G$
Option: 4 $-20 G$

Answers (1)

best_answer

We know that, for spherical shell

$V_{0}= \frac{-GM}{R}\\$ $\left [0< r\leq R \right ]\\$

But $V= \frac{-GM}{R}\: -\frac{GM}{r}\\$ (Given)

$V= \frac{-G(100)}{50}-\frac{G(50)}{25}\\$

$V= -4G$

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vishal kumar

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