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A particle is moving eastwards with a velocity of  5 m/s. In 10 s the velocity changes to 5 m/s northwards. The average acceleration in this time is

Option: 1

Zero


Option: 2

\frac{1}{\sqrt{2}}ms ^{-2} towards north-­west


Option: 3

\frac{1}{\sqrt{2}}ms ^{-2} towards north­-east


Option: 4

\frac{1}2ms ^{-2} towards north


Answers (1)

best_answer

Velocity in the east direction  = 5\hat{i}

Velocity in the north direction  = 5\hat{j}

      Acceleration     \vec{a}= \frac{5\hat{j}-5\hat{i}}{10}

or    \vec{a}=\frac{1}{2}\hat{j}-\frac{1}{2}\hat{i}\: or\: \left |\vec{a} \right |\sqrt{\left ( \frac{1}{2} \right )^{2}+\left ( -\frac{1}{2} \right )^{2}}

         |\vec{a}|=\frac{1}{\sqrt{2}} m s^{-2} \text { towards north west }    

Posted by

Shailly goel

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