Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A particle is moving in uniform circular motion ,the acceleration at a point P(R,) on the circle of radius R is (H

A particle is moving in uniform circular motion ,the acceleration at a point P(R,\theta) on the circle of radius R is (Here \theta is measured from the X-axis)

Option: 1

\frac{V^2}{R}\hat{i}+\frac{V^2}{R}\hat{j}


Option: 2

-\frac{V^2}{R}\cos\theta\hat{i}+\frac{V^2}{R}\sin\theta\hat{j}


Option: 3

-\frac{V^2}{R}\sin\theta\hat{i}+\frac{V^2}{R}\cos\theta\hat{j}


Option: 4

-\frac{V^2}{R}\cos\theta\hat{i}-\frac{V^2}{R}\sin\theta\hat{j}


Answers (1)

best_answer

as we learned 

Uniform circular motion -

If a object moves in a circular path with a  constant speed, then its motion is known as uniform circular motion.

- wherein

Fig. Shows Uniform  circular of motion

 

 

 

acceleration a:\frac{V^{2}}{R} towards the centre 

From figure:

\vec{a}=-acos\theta\hat{i}-asin\theta\hat{j}

=-\frac{V^{2}}{R}cos\theta\hat{i}-\frac{V^{2}}{R}sin\theta\hat{j}

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22
anam-khan

JEE Main 2025: NIT Tiruchirappalli saw stable preference in Civil Engineering cut-offs; 3 year trend analysis
anam-khan

JEE Main 2025: Grabbing BTech CSE seat at NIT tougher for economically weaker aspirants

Latest Question