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A projectile fired with initial velocity  v at an angle \theta. If initial velocity be tripled at the same angle of projection, then time of ascent will become 

Option: 1

Three times the original time of ascent


Option: 2

Two times the original time of ascent


Option: 3

Four times the original time of ascent


Option: 4

Five times the original time of ascent


Answers (1)

best_answer

Assuming no air resistance, the time of ascent of a projectile launched at an angle  \theta with initial velocity v is given by:

t = (v*sin\theta) / g

where g is the acceleration due to gravity (approximately 9.8 m/s^2).

If the initial velocity is tripled while keeping the launch angle \theta constant, the new initial velocity is 3v Therefore, the new time of ascent,t', is given by:

t' = (3v*sin\theta) / g

To find the ratio of t' to t, we can divide t' by t:

t'/t = [(3vsin\theta) / g] / [(vsin\theta) / g]

t'/t = 3

Therefore, if the initial velocity is tripled while keeping the launch angle constant, the time of ascent of the projectile will become three times the original time of ascent.

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