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A ray incident at a point as an angle of incidence of 60^{\circ} enters a glass sphere of refractive index \mathrm{n=\sqrt{3}} and is reflected and refracted further at the surface of the sphere. The angle between the reflected and refracted rays at this surface is:

Option: 1

50^{\circ}


Option: 2

60^{\circ}


Option: 3

90^{\circ}


Option: 4

40^{\circ}


Answers (1)

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We have, refractive index, \mu=\frac{\sin \mathrm{i}}{\sin \mathrm{r}} \Rightarrow \sqrt{3}=\frac{\sin 60^{\circ}}{\sin \mathrm{r}}

Refracted angle, \mathrm{r=30^{\circ}}
The angle between the reflected and refracted rays \mathrm{\Theta =180^{\circ}-i-r=90^{\circ}}

Posted by

Kuldeep Maurya

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