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A ray of light is incident from air on a glass plate having thickness \sqrt{3} cm and refractive index \sqrt{2} The angle of incidence of a ray is equal to the critical angle for glass-air interface. The lateral displacement of the ray when it passes through the plate is _______\times 10^{-2} \mathrm{~cm} \text {. (given } \sin 15^{\circ}=0.26 \text { ) }

Option: 1

52


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer


\sin c=\frac{1}{\sqrt{2}} \Rightarrow c=45^{\circ}
Using Snell’s law on 1st surface, sinc = \sqrt{2} \sin r
                                                      \Rightarrow \sin r=\frac{1}{2} \Rightarrow r=30^{\circ}
d=t \operatorname{secr} \times \sin (c-r)=\sqrt{3} \times \frac{2}{\sqrt{3}} \times 0.26=0.52 \mathrm{~cm}=52 \times 10^{-2} \mathrm{~cm}

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Sayak

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