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  • A tennis ball is dropped on to the floor from a height of 9.8 m.It rebounds to a height 5.0 m. Ball comes in contact with the floor for 0.2 s. The average acceleration during contact is ms<sup

A tennis ball is dropped on to the floor from a height of 9.8 m.It rebounds to a height 5.0 m. Ball comes in contact with the floor for 0.2 s. The average acceleration during contact is ms−2
(Given g = 10 ms−2)

Option: 1

120


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & v_1=\sqrt{2 g h}=\sqrt{2 \times 10 \times 9.8}=\sqrt{196} \\ & v_1=14 \mathrm{~m} / \mathrm{sec} \\ & v_2=\sqrt{2 g h} \\ & \mathrm{v}_2=\sqrt{2 \times 10 \times 5}=10 \mathrm{~m} / \mathrm{sec} \\ & a_{\text {avg }}=\frac{\Delta v}{\Delta t}=\frac{\vec{v}_2-\vec{v}_1}{\Delta t}=\frac{10-(-14)}{0.2} \\ & a_{avg}=\frac{24}{0.2}=120 \mathrm{~m} / \mathrm{sec}^2 \end{aligned}

Posted by

Gautam harsolia

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