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  • A train is standing on a platform, a man inside a compartment of a train drops a stone. At the same instant train starts to move with constant acceleration . The path of the particle as seen by the pe

A train is standing on a platform, a man inside a compartment of a train drops a stone. At the same instant train starts to move with constant acceleration . The path of the particle as seen by the person who drops the stone is :
Option: 1 Parabola

Option: 2

straight line for sometime & parabola for the remaining time


Option: 3

straight line


Option: 4 variable path that cannot be defined

Answers (1)

best_answer

As we have learnt in

 

2nd equation or Position- time equation -

s= ut +\frac{1}{2}at^{2}

s\rightarrow Displacement

u\rightarrowInitial velocity

a\rightarrowacceleration

t\rightarrow time

 

-

 

 

Relative to the person in the train, acceleration of the stone is ‘g’ downward, a (acceleration of train) backwards. 

According to him  : X=\frac{1}{2}\: at^{2},\; Y=\frac{1}{2}\: gt^{2}

\Rightarrow \frac{X}{Y}=\frac{a}{g}\Rightarrow Y=\frac{9}{a}X\Rightarrow straight\; line.

 

Posted by

Ritika Harsh

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