Get Answers to all your Questions

header-bg qa

An alkyne (P) on hydration with \mathrm{H_2SO_4} in the presence of \mathrm{HgSO_4} forms 3 - Methylbutan - 2 - one as the major product. The alkyne (P) is 

Option: 1

3 - Methylbut - 1 - yne
 


Option: 2

2 - Methylbut - 3 - yne


Option: 3

3 - Methylbut - 2 - yne


Option: 4

3 - Methylbut - 3 - yne


Answers (1)

best_answer

As we have learnt,

Hydration of Alkynes follow Markovnikov addition without rearrangement

Hence, the correct answer is Option (1)

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE