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An astronaut is looking down on Earth's surface from a space shuttle at an altitude of \mathrm{400 \mathrm{~km}}. Assuming that the astronaut's pupil diameter is 5 \mathrm{~mm} and the wavelength of visible light is \mathrm{500 \mathrm{~nm}}, the astronaut will be able to resolved linear objects of the size of about:

Option: 1

0.5 m


Option: 2

5 m


Option: 3

50 m


Option: 4

500 m


Answers (1)

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\mathrm{\begin{aligned} & \text { As } \mathrm{d} \theta=\frac{\mathrm{x}}{\mathrm{d}}=\frac{1.22 \lambda}{\mathrm{D}}, \quad \therefore \quad \mathrm{x}=\frac{1.22 \lambda \mathrm{d}}{\mathrm{D}} \\\\ & =\frac{1.22\left(500 \times 10^{-9} \mathrm{~m}\right)\left(400 \times 10^3 \mathrm{~m}\right)}{\left(5 \times 10^{-3} \mathrm{~m}\right)}=48.8 \mathrm{~m} \approx 50 \mathrm{~m} \end{aligned}}

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Ritika Kankaria

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