Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Angular width of a central max. is 300 when the slit is illuminated by light of wavelength 6000 <img alt="\mathrm{\AA}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%

Angular width of a central max. is 300 when the slit is illuminated by light of wavelength 6000 \mathrm{\AA}. Then width of the slit will be approx.

Option: 1

\mathrm{12 \times 10^{-6} \mathrm{~m}}


Option: 2

\mathrm{12 \times 10^{-7} \mathrm{~m}}


Option: 3

\mathrm{12 \times 10^{-8} \mathrm{~m}}


Option: 4

\mathrm{12 \times 10^{-9} \mathrm{~m}}


Answers (1)

best_answer

\mathrm{\begin{aligned} & \text { Angular width }=2 \theta=30^{\circ} \\ & \therefore \sin 30^{\circ}=\frac{\lambda}{a} \\ & \therefore \mathrm{a}=\frac{\lambda}{\sin 30^0}=\frac{6000 \times 10^{-10}}{1 / 2}=12000 \times 10^{-10} \mathrm{~m} \\ & =12 \times 10^{-7} \mathrm{~m} \\ & \end{aligned}}

Posted by

jitender.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering courses
anam-khan

JEE Main 2026: NIT Delhi cut-offs for BTech courses show ever-increasing demands for AI, computer skills
anam-khan

597 Eklavya school students clear JEE, NEET exams in 2024-25; Gujarat, MP lead

Latest Question