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  • Arrange the following conformational isomers of n-butane in order of their increasing potential energy : Option: 1 <img

Arrange the following conformational isomers of n-butane in order of their increasing potential energy :
Option: 1 \begin{aligned} &\mathrm{I}<\mathrm{III}<\mathrm{IV}<\mathrm{II} \\ \end{aligned}
Option: 2 \mathrm{I}<\mathrm{IV}<\mathrm{III}<\mathrm{II} \\
Option: 3 \mathrm{II}<\mathrm{IV}<\mathrm{III}<\mathrm{I} \\
Option: 4 \mathrm{II}<\mathrm{III}<\mathrm{IV}<\mathrm{I}

Answers (1)

best_answer

The stability of Corformers of Butane is

\mathrm{Anti> Gauche> Partial \: Eclipsed> Fully\: eclipsed}

\mathrm{(I)}            \mathrm{(III)}                \mathrm{(IV)}                                 \mathrm{(II)}

Thus the order of potential energy will be the reverse of stability order

\mathrm{II> IV> III> I}

Hence the correct answer is option (1)

Posted by

sudhir kumar

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