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  • As shown in the figure, after passing through the medium 1 . The speed of light in medium

As shown in the figure, after passing through the medium 1 . The speed of light \mathrm{v_{2}} in medium 2 will be :


(Given \mathrm{c}=3 \times 10^{8} \mathrm{~ms}^{-1} )
    
 

Option: 1

1.0 \times 10^{8} \mathrm{~ms}^{-1}


Option: 2

0.5 \times 10^{8} \mathrm{~ms}^{-1}


Option: 3

1.5 \times 10^{8} \mathrm{~ms}^{-1}


Option: 4

3.0 \times 10^{8} \mathrm{~ms}^{-1}


Answers (1)

best_answer

\mathrm{V =\frac{c}{\sqrt{\mu_r \varepsilon_r}} }

\mathrm{V_1 =\frac{c}{\sqrt{\left(u_r\right)_1\left(\varepsilon _r\right)_1}}=1.5 \times 10^8 \mathrm{~m} / \mathrm{s} }

\mathrm{V_2 =\frac{c}{\sqrt{\left(u_r\right)_2\left(\varepsilon _r\right)_2}}=\frac{3 \times 10^8}{3} }

      \mathrm{=10^8 \mathrm{~m} / \mathrm{s}}

Hence 1 is correct option.

Posted by

Deependra Verma

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