The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s doubleslit experiment is
infinite
five
three
zero.
As we learnt in
Fraunhofer Diffraction -
- wherein
Condition of nth minima.
slit width
angle of deviation
For interference maxima
This equation is satisfied if is never greater than (+1), less than (-1)
Maximum number of maxima can be five.
Correct option is 2.
Option 1)
infinite
This is an incorrect option.
Option 2)
five
This is the correct option.
Option 3)
three
This is an incorrect option.
Option 4)
zero.
This is an incorrect option.
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