Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

In a double slit experiment, when a thin film of thickness t having refractive index \mu is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is ( \lambda is the wavelenth of the light used) :

  • Option 1)

    \frac{\lambda}{2(\mu-1)}

  • Option 2)

    \frac{2\lambda}{(\mu-1)}

  • Option 3)

    \frac{\lambda}{(2\mu-1)}

  • Option 4)

    \frac{\lambda}{(\mu-1)}

 

Answers (1)

best_answer

In YDSE

\triangle X=(\mu-1)\frac{tD}{d}=\beta = \frac{\lambda D}{d}

\Rightarrow t=\frac{\lambda}{(\mu-1)}


Option 1)

\frac{\lambda}{2(\mu-1)}

Option 2)

\frac{2\lambda}{(\mu-1)}

Option 3)

\frac{\lambda}{(2\mu-1)}

Option 4)

\frac{\lambda}{(\mu-1)}

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 Registration LIVE: NTA JEE form at jeemain.nta.nic.in; what's new this year?
anam-khan

JEE Main 2026: Wider gap in NIT cut-offs for home and other-state quotas; outsiders need better rank
anam-khan

JEE Mains 2026: Use of calculator 'not allowed’ says NTA; cites ‘typographical error' in information bulletin

Latest Question