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Consider the following reaction approaching equilibrium at 27^{\circ}C and 1 atm pressure

\mathrm{A}+\mathrm{B} \underset{k_r=10^2}{\stackrel{\mathrm{k}_{\mathrm{f}}=10^3}{\rightleftharpoons}} C+D

The standard Gibb's energy change  \left(\Delta_{\mathrm{r}} G^\theta\right) at 27^{\circ}C is (–)______KJ \; mol^{-1}

(Nearest integer).

(Given: \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}and ln 10 = 2.3 )

Option: 1

6


Option: 2

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Option: 3

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Option: 4

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Answers (1)

best_answer

\begin{aligned} & \mathrm{K}_{\mathrm{eq}}=\frac{\mathrm{K}_{\mathrm{f}}}{\mathrm{K}_{\mathrm{b}}}=\frac{10^3}{10^2}=10 \\ & \Delta \mathrm{G}^{\mathrm{o}}=-\mathrm{RT} \ln \mathrm{K}_{\mathrm{cq}} \\ & =-8.3 \times 300 \ln 10 \\ & =-8.3 \times 300 \times 2.3 \\ & =-5.72 \times 10^{+3} \mathrm{~J} \\ & =5.72 \mathrm{KJ}\end{aligned}

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Gautam harsolia

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