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Consider the reaction of propene with HBr as given below

\mathrm{CH_3-CH =CH_2\xrightarrow[]{HBr}(P)}


\mathrm{CH_3-CH =CH_2\xrightarrow[H_2O_2]{HBr}(Q)}

The major product (P) and (Q) are related to each other as

Option: 1

Identical


Option: 2

Positional isomers


Option: 3

Chain isomers


Option: 4

Not isomers


Answers (1)

best_answer

HBr gives Markovnikov's addition product while HBr in presence of peroxide gives Anti Markovnikov's addition product

 

(P) and (Q) are positional isomers.
Hence, the correct answer is option (2).

Posted by

shivangi.bhatnagar

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