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  • Cosider the following reaction : <img alt="\mathrm{2 \mathrm{HSO}_{4}^{-}(\mathrm{aq})\xrightarrow[(2)Hydrolysis]{(1)Electrolysis} 2 \mathrm{HSO}_{4}^{-}+2 \mathrm{H}^{+}+\mathbf{A}}" src

Cosider the following reaction :

\mathrm{2 \mathrm{HSO}_{4}^{-}(\mathrm{aq})\xrightarrow[(2)Hydrolysis]{(1)Electrolysis} 2 \mathrm{HSO}_{4}^{-}+2 \mathrm{H}^{+}+\mathbf{A}}

The dihedral angle in product \mathbf{A} in its solid phase at 110 \mathrm{~K} is :
 

Option: 1

104^{\circ}


Option: 2

111.5^{\circ}


Option: 3

90.2^{\circ}


Option: 4

111.0^{\circ}


Answers (1)

best_answer

\mathrm{2 \mathrm{HSO}_{4}^{-}(\mathrm{aq})\xrightarrow[(ii)Hydrolysis]{(i)Electrolysis} 2 \mathrm{HSO}_{4}^{-}+2 \mathrm{H}^{+}+\mathrm{H_{2}O_{2}}}


\mathrm{A= H_{2}O_{2}}  in solid phase

from figure,


The dihedral angle of \mathrm{H_{2}O_{2}} in solid phase is \mathrm{90.2^{\circ}}

Option (3) is correct.

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mansi

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