Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Following figure shows sources and <img alt="\mathrm{\mathrm{S}_2}" src="https://entrancecorner.o

Following figure shows sources \mathrm{S}_1 and \mathrm{\mathrm{S}_2} that emits light of wavelength \mathrm{\lambda} in all directions. The sources are exactly in phase and are separated by a distance equal to \mathrm{1.5\, \, \lambda} . If we start at the indicated start point and travel along path 1 and 2 , the interference produce a maxima all along

 

Option: 1

Path 1
 


Option: 2

Path 2
 


Option: 3

Any path
 


Option: 4

None of these


Answers (1)

best_answer

At any point along the path 1 , path difference between the waves is 0 .

Hence maxima is obtained all along the path 1.

At any point along the path 2 , path difference is \mathrm{1.5 \lambda} which is odd multiple of \mathrm{\frac{\lambda}{2},} so minima is obtained all along the path 2 .

Posted by

Nehul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow
anam-khan

JEE Main 2026 Registration LIVE: Session 2 exam from April 2 to 9; shift timings, admit card, exam pattern
anam-khan

JEE Main 2026 session 2 registration ends today for BTech, BArch; apply at jeemain.nta.nic.in

Latest Question