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  • From the v – t graph shown, the ratio of distance to displacement in 25 s of motion is : <img alt="" src="https://cdn.entrance360.com/media/uploads/2023/05/15/image2.PNG" style="hei

From the v – t graph shown, the ratio of distance to displacement in 25 s of motion is :

Option: 1

\frac{3}{5}


Option: 2

\frac{1}{2}


Option: 3

\frac{5}{3}


Option: 4

1


Answers (1)

Displacement = Area of graph with sign
\begin{aligned} & \text { Displacement }=\left(\frac{1}{2} \times 10 \times 5\right)+(10 \times 5)+\left(\frac{1}{2} \times 5 \times 30\right)+\left(\frac{1}{2} \times 5 \times 20\right)-\frac{1}{2}(5)(20) \\ & =25+50+75+50-50 \\ & =150 \mathrm{~m} \end{aligned}
Distance \rightarrow Area of graph with positive value
Distance =25+50+75+50=250

\frac{\text { Distance }}{\text { Displacement }}=\frac{250}{150}=\frac{5}{3} \quad

 

Posted by

Kshitij

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