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If two waves represented by Y1 = 4 sin wt and Y_{2}=3sin\left ( wt +\frac{\pi }{3}\right )  interfere at a point, the amplitude of the resulting wave will be about:

  • Option 1)

    7

  • Option 2)

    6

  • Option 3)

    5

  • Option 4)

    3.5

 

Answers (1)

best_answer

 

 

Resultant amplitude of two wave -

 

A= \sqrt{{A_{1}}^{2}+{A_{2}}^{2}+2A_{1}A_{2}\cos \theta }
 

- wherein

A_{1}= amplitude of wave 1

A_{2}=  amplitude of wave 2

\theta = phase difference

 

 A= \sqrt{{A_{1}}^{2}+{A_{2}}^{2}+2A_{1}A_{2}\cos \delta }

A_{1} = 4 ,A_{2} = 3, and\ \delta = 60

 

A= \sqrt{3^{2}+4^{2}+2.3.4.\frac{1}{2} }

= \sqrt{37} = 6

 


Option 1)

7

Incorrect

Option 2)

6

Correct

Option 3)

5

Incorrect

Option 4)

3.5

Incorrect

Posted by

Plabita

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