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  • Help me answer: - Sets, Relations and Functions - BITSAT

Let A and B be two sets containing 2 elements and 4 elements respectively. The number of subsets of A\timesB having 3 or more elements is :

  • Option 1)

    211

  • Option 2)

    256

  • Option 3)

    220

  • Option 4)

    219

 

Answers (2)

best_answer

n(A) = 4, n(B) = 2

n(A\times B)=8

Number of sbsets having atlest 3 elements

=2^{8}-\left(1+^{8}C_{1}+^{8}C_{2} \right )=219


Option 1)

211

Incorrect

Option 2)

256

Incorrect

Option 3)

220

Incorrect

Option 4)

219

Correct

Posted by

Aadil

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