Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

if 4\sin ^{2}\alpha =1, then the values of \alpha are

  • Option 1)

    2n\pi \pm \frac{\pi}{3}, n\epsilon Z

  • Option 2)

    n\pi \pm \frac{\pi}{3}, n\epsilon Z

  • Option 3)

    n\pi \pm \frac{\pi}{6}, n\epsilon Z

  • Option 4)

    2n\pi\pm\frac{\pi}{6}, n\epsilon Z

 

Answers (1)

best_answer

As we learnt in

Results from General Solution -

 If \sin ^{2}\Theta = \sin ^{2}\alpha

    \cos ^{2}\Theta = \cos ^{2}\alpha

    \tan ^{2}\Theta = \tan ^{2}\alpha

then \Theta = n\pi \pm \alpha

- wherein

\alpha is the given angle

 

 

4\sin ^{2}\alpha =1

\sin \alpha \pm \frac{1}{2}

\alpha = n\pi \pm \frac{\pi }{6}\ \: \: \: \: \: n\epsilon Z    \\ \left[ \because sin^{2}x=sin^{2}\alpha \right; \left x=n\pi \pm \alpha \right ]

 

 


Option 1)

2n\pi \pm \frac{\pi}{3}, n\epsilon Z

This option is incorrect.

Option 2)

n\pi \pm \frac{\pi}{3}, n\epsilon Z

This option is incorrect.

Option 3)

n\pi \pm \frac{\pi}{6}, n\epsilon Z

This option is correct.

Option 4)

2n\pi\pm\frac{\pi}{6}, n\epsilon Z

This option is incorrect.

Posted by

divya.saini

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2025 registration link active at bitsadmission.com; exam schedule, eligibility criteria
anam-khan

BITSAT 2025 registration begins today for 10 BE, 6 MSc, BPharm courses; eligibility, fee
anam-khan

BITSAT 2025 registration from tomorrow at bitsadmission.com; eligibility criteria

Latest Question