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  •  If boat travels at some angle  with river flow (u) having its Speed  w.r.t. River=v Then time taken to c

 If boat travels at some angle \theta with river flow (u) having its Speed  w.r.t. River=v Then time taken to cross the river is

Option: 1

t= \frac{d}{u\sin \theta }
 


Option: 2

t= \frac{d}{u\cos \theta }


Option: 3

t= \frac{u\cos \theta }{d}

 


Option: 4

t= \frac{u\sin \theta }{d}


Answers (1)

best_answer

 

If boat travels at some angle \theta with river flow (u)

 

        Now resolve v in two component

        Component of v along  U = v_x=vcos\theta\hat{i}

        Component of v perpendicular to U = v_y=vsin\theta\hat{j}

               So,V_b=(vcos\theta +u)\hat{i}+vsin\theta\hat{j}

  

        and,    \left | V_b \right |= \sqrt{u^2+v^2+2uvcos\theta }

         Now if time taken to cross the river is t

        Then,   t=\frac{d}{vsin\theta }

 

 

 

 

 

Posted by

Ritika Jonwal

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