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If cosx=-\frac{11}{4} , x lies in third quadrant, then the value of sin \; x is 

Option: 1

-\frac{105}{16}


Option: 2

\frac{105}{16}


Option: 3

\frac{109}{16}


Option: 4

-\frac{109}{16}


Answers (1)

best_answer

Given  cos\: x=-\frac{11}{4},    lies in the third quadrant.

We know that  sin^2x+cos^2x=1

        Implies sin^2x=1-cos^2x

                                 =1-\left ( \frac{11}{4} \right )^2

                                =1-\left ( \frac{121}{16} \right )

                                =\frac{16-121}{16}

                                =-\frac{105}{16}

                                   

                                    

                                   

                                   

Posted by

Ritika Jonwal

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