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If sinx=\frac{2}{3} , x lies in the first quadrant, then the value of cos \: x is

Option: 1

\frac{5}{2}


Option: 2

\frac{\sqrt{5}}{3}


Option: 3

\frac{3}{2}


Option: 4

\frac{\sqrt{5}}{2}


Answers (1)

best_answer

Given sinx=\frac{2}{3} , x lies in the first quadrant.

We know that the formula,

\sin ^2\Theta +\cos ^2\Theta =1

Implies cos^2x=1-sin^2x

                           =1-\frac{4}{9}

              cos^2x=\frac{5}{9}

Then, cosx=\frac{\sqrt{5}}{3}

 

Posted by

Suraj Bhandari

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