Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

If in a $\bigtriangleup ABC,$ the altitudes from the vertices $A,B,C$ on opposite sides are in $H.P.$ .,

then $\sin A,\sin B,\sin C$ are in
Option: 1
$H.P.$

Option: 2
$Arithmetic-Geometric \: progression$

Option: 3
$A.P.$

Option: 4
$G.P.$

Answers (1)

best_answer

We AD = ha althide from a

then $\frac{1}{2}aha = \frac{1}{2}bhb= \frac{1}{2}chc$

Thus $a = \frac{k}{ha}, b= \frac{k}{hb}, c= \frac{k}{hc}$

when k= is some content -------- $\left ( 1 \right )$

Now $ha, hb, hc$ in HP

$\Rightarrow \frac{2}{hb} = \frac{1}{ha} +\frac{1}{hc} ---- \left ( 2 \right )$

$\left ( 1 \right ) and \left ( 2 \right ) we\: get$

$2b= a+c, here$

$= A.P$

Posted by

Shailly goel

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 exam date soon; syllabus, previous years' question papers, books for preparation

anam-khan

JEE Main 2025 exam date this month; updates on reduced syllabus, registration, number of attempts

Latest Question