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  • If is the gravitational potential due to sphere of uniform density on it's surface, then it's

If \mathrm{V} is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:-

Option: 1

\frac{4}{3} \mathrm{~V}


Option: 2

\mathrm{V}


Option: 3

\frac{3 \mathrm{~V}}{2}


Option: 4

\frac{V}{2}


Answers (1)

best_answer

V=-\frac{G M}{R^{3}}\left(1.5 R^{2}-0.5 r^{2}\right)

V=-\frac{G M}{R} \text { [At the surface] }

V_{\text {centre }}=-\frac{3 G M}{2 R}=\frac{3}{2} V

Posted by

Pankaj

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