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If prism angle \mathrm{\alpha=1^{\circ}, \mu=1.54}, distance between screen and prism (b) \mathrm{=0.7 \mathrm{~m}}, distance between prism and source

\mathrm{a=0.3 \mathrm{~m}, \lambda=180 \pi \mathrm{nm}} then in Fresnal biprism find the value of \mathrm{\beta } (fringe width)

Option: 1

\mathrm{10^{-4} \mathrm{~m}}


Option: 2

\mathrm{10^{-3} \mathrm{~mm}}


Option: 3

\mathrm{10^{-4} \times \pi \mathrm{m}}


Option: 4

\mathrm{10^{-4} \times \pi \mathrm{m}}


Answers (1)

best_answer

\mathrm{\text { By using } \beta=\frac{(a+b) \lambda}{2 a(\mu-1) \alpha}=\frac{(0.3+0.7) \times 180 \pi \times 10^{-9}}{2 \times 0.3(1.54-1) \times\left(1 \times \frac{\pi}{180}\right)}=10^{-4} \mathrm{~m}}

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Ajit Kumar Dubey

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