Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If speed (V), accerleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be

If speed (V), accerleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be

Answers (1)

The unit of speed is L/T , acceleration is L/T² and that of force is ML/T². Since Y=FL/eA, where 'e' is the length change.(area unit is L²)

Y=ML*L/L*T²*L²=M/LT²

Posted by

Divya Karri

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 City Intimation Slip LIVE: NTA session 1 city slip soon; exam from January 21
anam-khan

JEE Mains: Delhi HC dismisses response sheet tampering plea; orders students to do community service
anam-khan

JEE Mains 2026: NTA extends photo verification deadline for non-Aadhaar candidates to January 15

Latest Question