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If the acceleration due to gravity experienced by a point mass at a height \mathrm{ h} above the surface of earth is same as that of the acceleration due to gravity at a depth \alpha \mathrm{h}\left(\mathrm{h}<\mathrm{R}_{\mathrm{e}}\right) from the earth surface. The value of \alpha will be__________ (use \mathrm{R}_{\mathrm{e}}=6400 \mathrm{~km} )

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{g_h =g_d }

\mathrm{{\text {depth }} =d=\alpha h }

\mathrm{\left(h<<R_e\right) }

\mathrm{\therefore g\left(1-\frac{2 h}{R}\right) =g\left(1-\frac{d}{R}\right) }

\mathrm{1-\frac{2 h}{R} =1-\frac{\alpha h}{R} }

\mathrm{\alpha =2}

The value of \mathrm{\alpha } is \mathrm{2 }





 

Posted by

Pankaj Sanodiya

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