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If f(x)=\frac{x+2}{x-2} then f'(-1) is

Option: 1

2/3


Option: 2

-2/3


Option: 3

4/9


Option: 4

-4/9


Answers (1)

best_answer

Given that f(x)=\frac{x+2}{x-2},

\\ f'(x)=\frac{d(f(x))}{dx}=\frac{(x-2)\frac{d(x+2)}{dx}-(x+2)\frac{d(x-2)}{dx}}{(x-2)^2} \\ f'(x)=\frac{d(f(x))}{dx}=\frac{-4}{(x-2)^2} \\ f'(-1)=\frac{d(f(x))}{dx}=\frac{-4}{(-1-2)^2}=\frac{-4}{9}

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Kuldeep Maurya

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