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  • In a single slit diffraction of light of wavelength by a slit of width e, the size of t

In a single slit diffraction of light of wavelength \mathrm{\lambda} by a slit of width e, the size of the central maximum on a screen at a distance b is

Option: 1

\mathrm{2 b \lambda+e}


Option: 2

\mathrm{\frac{2 b \lambda}{\mathrm{e}}}


Option: 3

\mathrm{\frac{2 b \lambda}{e}+e}


Option: 4

\mathrm{\frac{2 b \lambda}{e}-e}


Answers (1)

best_answer

The direction in which the first minima occurs is \theta (say).

\mathrm{Then \mathrm{e} \sin \theta=\lambda or \mathrm{e} \theta=\lambda \, or, \theta=\frac{\lambda}{\mathrm{e}}(\because \theta=\sin \theta \, when \, \theta \, small)} 
Width of the central maximum \mathrm{=2 b \theta+e=2 b \cdot \frac{\lambda}{e}+e}

Posted by

HARSH KANKARIA

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