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In Young's double slit experiment how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringe if \mathrm{\lambda=2000 \, \AA} and \mathrm{ \mathrm{d}=7000 \, \, \AA}

Option: 1

12


Option: 2

7


Option: 3

18


Option: 4

4


Answers (1)

best_answer

For maximum intensity on the screen
\mathrm{ \mathrm{d} \sin \theta=\mathrm{n} \lambda \Rightarrow \sin \theta=\frac{\mathrm{n} \lambda}{\mathrm{d}}=\frac{\mathrm{n}(2000)}{7000}=\frac{\mathrm{n}}{3.5} }
Since maximum value of \sin \theta is 1

So \mathrm{\mathrm{n}=0,1,2,3}, only. Thus only seven maximas can be obtained on both sides of the screen.

Posted by

Divya Prakash Singh

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