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  • In Young's double slit experiment, how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringes, if <img alt="\mathrm{\lambda=2000 \AA}" src

In Young's double slit experiment, how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringes, if \mathrm{\lambda=2000 \AA} and \mathrm{7000 \, \AA} ?

Option: 1

12


Option: 2

7


Option: 3

18


Option: 4

4


Answers (1)

best_answer

For maximum (brightness) intensity of the screen, path difference should be integer multiple of wavelength, i.e.,

\mathrm{ \begin{aligned} & \mathrm{d}=\sin \theta=\mathrm{n} \lambda \\ & \sin \theta=\frac{\mathrm{n} \lambda}{\mathrm{d}}=\frac{\mathrm{n}(2000)}{7000}=\frac{\mathrm{n}}{3.5} \end{aligned} }

As, \mathrm{(\sin \theta)_{\max }=1}

So, \mathrm{\quad \mathrm{n}=0,1,2,3}
Thus, only seven maximas can be obtained on both sides of the screen.

Posted by

sudhir kumar

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