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In Young's double slit experiment, the \mathrm{10^{\text {th }}} maximum of wavelength \mathrm{\lambda_1} is at a distance of \mathrm{y_1} from the central maximum. When the wavelength of the source is changed to \mathrm{\lambda_2, 5^{\text {th }}} maximum is at a distance of \mathrm{y_2} from its central maximum. The ratio \mathrm{\left(\frac{\mathrm{y}_1}{\mathrm{y}_2}\right)} is:

Option: 1

\mathrm{\frac{2 \lambda_1}{\lambda_2}}


Option: 2

\mathrm{\frac{2 \lambda_2}{\lambda_1}}


Option: 3

\mathrm{\frac{\lambda_1}{2 \lambda_2}}


Option: 4

\mathrm{\frac{\lambda_2}{2 \lambda_1}}


Answers (1)

best_answer

\mathrm{\text { We have, } \mathrm{y}_1=10 \omega_1=\frac{10 \lambda_1 \mathrm{D}}{\mathrm{d}}, \mathrm{y}_2=5 \omega_2=\frac{5 \lambda_2 \mathrm{D}}{\mathrm{d}}}

\mathrm{\therefore \frac{\mathrm{y}_1}{\mathrm{y}_2}=\frac{2 \lambda_1}{\lambda_2}}

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Nehul

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