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  • In Young,s double slit experiment the two slits are distance apart. Interference pattern is o

In Young,s double slit experiment the two slits are \mathrm{0.6mm} distance apart. Interference pattern is observed on a screen at a distance \mathrm{80cm} from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be __________\mathrm{nm}.

Option: 1

450


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{d=0.6 \mathrm{~mm}, \quad D=80 \mathrm{~cm}}.

For dark fringe

\mathrm{y=(2 n-1) \frac{D \lambda}{2 d}}

For 1st dark \mathrm{n=1}

\mathrm{y=\frac{D \lambda}{2 d}}

\mathrm{0.3 \mathrm{~mm} =\frac{80 \mathrm{~cm} \times \lambda}{2 \times 0.6 \mathrm{~mm}}} \\

\mathrm{\lambda =450 \mathrm{~nm}}

Hence the answer is \mathrm{450 \mathrm{~nm}}

Posted by

Ritika Jonwal

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