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  • In Young's double slit experimental setup, if the wavelength alone is doubled, the band width  <img alt="\mathrm{\beta}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%5

In Young's double slit experimental setup, if the wavelength alone is doubled, the band width  \mathrm{\beta} becomes: 

Option: 1

\mathrm{\frac{\beta}{2} }


Option: 2

\mathrm{2 \beta }


Option: 3

\mathrm{ 4 \beta }


Option: 4

\mathrm{\beta}


Answers (1)

best_answer

Fringe width, \mathrm{ \beta=\frac{\lambda D}{d}}                          \mathrm{ (i)}

Where \mathrm{ \lambda} is the wavelength of the light, \mathrm{ \mathrm{D}} is the distance between the slits and the screen and \mathrm{ \mathrm{d}} is the distance between two slits.

When \mathrm{ \lambda} alone is doubled, while the other parameters remain unchanged, then fringe width becomes

\mathrm{ \beta^{\prime}=\frac{(2 \lambda) D}{d}=2 \beta }                                (Using (i))
 

Posted by

Rakesh

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