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Initially a car at rest accelerates uniformly to a speed of 144 Km/h in 20 sec . Then it covers a distance of

Option: 1
20 m

Option: 2
400 m

Option: 3
1440 m

Option: 4
12880 m

Answers (1)

best_answer

$v = u+ at$

$a = v/t$

$a = 40/20 = 2 m/s 2$

$s = ut + 1/2 at^{2}$

$0+1/2\times 2\times \left ( 20 \right )^{2}$

s $= 400$

Posted by

shivangi.bhatnagar

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