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It is found that when waves of same intensity from two coherent sources superpose at a certain point, then the resultant intensity is equal to the intensity of one wave only. This means that the phase difference between the two waves at the point is: 

Option: 1

\mathrm{\text { zero }}


Option: 2

\mathrm{\frac{\pi}{3}}


Option: 3

\mathrm{\frac{2 \pi}{3}}


Option: 4

\mathrm{\pi}


Answers (1)

best_answer

Intensity, \mathrm{I=4 \mathrm{I}_0 \cos ^2 \frac{\varphi}{2}}

\mathrm{ \begin{aligned} & \because \quad I=I_0 \\ & \therefore \quad \phi=\frac{2 \pi}{3} \end{aligned} }

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jitender.kumar

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