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  • Let AD and BC be two verticle pole of A&B on horizontal ground. If AD=8 and BC=11 and AB=10 then the distance of the point M on AB from the pt A st is

Let AD and BC be two verticle pole of A&B on horizontal ground. If AD=8 and BC=11 and AB=10 then the distance of the point M on AB from the pt A st MD^2+MC^2 is min is ....
Option: 1 4
Option: 2 5
Option: 3 6
Option: 4 7

Answers (1)

best_answer

\\f(x)=MD^{2}+MC^{2}=8^{2}+x^{2}+11^{2}+(10-x)^{2} \\ f^{\prime}(x)=2 x+2(10-x)(-1)=0 \\ 2 x=2(10-x) \\ x = 5 \\ f''(x) = 4 > 0 \Rightarrow $minima at x = 5$ \\ $Distance from point A i . e. AM$ = 5

Correct Answer : 5

Posted by

himanshu.meshram

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