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Light of wavelength\mathrm{ 2 \times 10^{-3} \mathrm{~m}} falls on a slit of width \mathrm{ 4 \times 10^{-3} \mathrm{~m}. }The angular dispersion of the central maximum will be:

Option: 1

30^{\circ}


Option: 2

60^{\circ}


Option: 3

90^{\circ}


Option: 4

180^{\circ}


Answers (1)

best_answer

Angular dispersion of central maximum \mathrm{ =} angular dispersion of \mathrm{ 1^{\text {st }}} minimum \mathrm{ (=2 \theta)} From,

\mathrm{ \sin \theta=\frac{\lambda}{\mathrm{d}}=\frac{2 \times 10^{-3}}{4 \times 10^{-3}}=\frac{1}{2}}

or  \mathrm{\theta=30^{\circ}}

\mathrm{ \therefore \quad 2 \theta=2 \times 30^{\circ}=60^{\circ} }

Posted by

shivangi.bhatnagar

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