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The equivalent conductivity of KCl at infinite dilution is 130 mho cm^2/eq. The transport number of Cl^- ion in KCl at the same temperature is 0.505. The transport number of K^+ ion\: is 

  • Option 1)

    0.495

  • Option 2)

    0.505

  • Option 3)

    0.0495

  • Option 4)

    Can't be determined

 

Answers (1)

best_answer

As we learnt in 

Conductivity -

Inverse of resistivity is called conductivity. \kappa = \frac{1}{\rho } 

- wherein

SI unit of Conductivity = Sm^{-1}

 

Transport number of Cl^{-}=0.505

but t_{cl^{-}}+t_{k^{+}}=1

t_{k^{+}}=1-0.505=0.495

\therefore Solution is 1


Option 1)

0.495

Correct

Option 2)

0.505

Incorrect

Option 3)

0.0495

Incorrect

Option 4)

Can't be determined

Incorrect

Posted by

prateek

View full answer

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